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Mathematics 17 Online
OpenStudy (anonymous):

Shark Inc. has determined that demand for its newest netbook model is given by lnq−3lnp+0.005p=7, where q is the number of netbooks Shark can sell at a price of p dollars per unit. Shark has determined that this model is valid for prices p≥100. You may find it useful in this problem to know that elasticity of demand is defined to be E(p)=dq/dp (p/q) a)Find E(p) Your answer should only be in terms of p b)What price will maximize revenue.

OpenStudy (anonymous):

It's actually lnq-3lnp+0.005p=7

OpenStudy (e.mccormick):

Are you looking for the derivative method?

OpenStudy (anonymous):

I tried getting q'(p/q) and I got 3-0.005p but that was wrong

OpenStudy (anonymous):

my q'=((3/p)-0.005)q

OpenStudy (e.mccormick):

Hmmm... well, did you do implicit differentiation because you have both variables in there?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

I don't know what I'm doing wrong

OpenStudy (primeralph):

Elasticity of demand is just dq/dp. Where is the other p/q factor from?

OpenStudy (anonymous):

I'm having so much trouble finding elasticity though.. I keep gettng 3-0.005p

OpenStudy (primeralph):

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