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3^(x+2)=8
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Since you cannot change 8 to the base 3, take logs of both sides.
[\log[3]3^(x+2) = \log[3]8\]
x+2 = log[3]8 so far?
x= log[3]8-2. Not sure if this is correct.
A bit hard for me to read/understand your notations.
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(x+2) log 3 = log 8 x + 2 = log 8/log 3 Therefore, x = (log 8/log 3) - 2 Is that what you have?
can you show me how you took the logs for both sides? I got something similar but not exactly that.
log (3^(x+2)) = (x+2) times log 3
or just (x+2) (log 3)
Got it, thanks so much!
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