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Mathematics 11 Online
OpenStudy (anonymous):

Is the relation {(0,2), (5,2), (-2,5), (3,4)} a function?

Directrix (directrix):

If the relation is a function, then a given x value can be paired with EXACTLY one y-value. Looking at the x = 0 coordinate, it is paired with 2 and only 2. So far, so good.

Directrix (directrix):

This is tricky here: (5,2), (-2,5). Many people see two 5s and automatically think that this relation is not a function. @cuitiefromthesouth2 Question. Look at (5,2) in the posted relation. Does the x value of 5 go with any number other than the 2? Yes or no.

OpenStudy (anonymous):

yes

Directrix (directrix):

Okay, where does the x value of 5 go in addition to the 2?

Directrix (directrix):

@cutiefromthesouth2 If you are looking at the ordered pair -->(-2,5), there is a 5 for a y-value. But, the value of x that goes with that 5 is -2 and not the 5 in (5,2). There can be no two-timing xs in a function. A particular x cannot go to two different y values for that x.

OpenStudy (anonymous):

oh okay, still a little confused

Directrix (directrix):

For a relation to be a function, there must be only and exactly one y that corresponds to a given x. Look at the attached diagram of a relation that is NOT a function.

OpenStudy (anonymous):

oh okay so its yes

Directrix (directrix):

Yours looks like this: Attached; your mapping.

Directrix (directrix):

You have a y that goes to two different xs but that is okay. It is when an x goes to two different y values that the relation is not a function.

Directrix (directrix):

@cuitiefromthesouth2 >>>> oh okay so its yes YES, that is correct.

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