Question

simplify 1n9 - 41n3

Answer 1

so is the 9 and 3 after exponents?

Answer 2

yea

Answer 3

Okay well subtracting exponents is easy, it's just like normal.

Answer 4

It would be also 1 minus 41 which is....you tell me

Answer 5

And then 9-3 which is.....

Answer 6

So therefore 1 minus 41 to the power of 9-3!

Answer 7

No... is this your equation?
\[\ln9 - 4\ln3 \]

Answer 8

@gary-jenkinson do you understand?

Answer 9

yea thats my equation

Answer 10

One sec.

Answer 11

@gary-jenkinson did you see what i wrote? do that

Answer 12

yea thanks :)

Answer 13

Gary, don't.

Answer 14

Okay great! Glad I could help.

Answer 15

Okay...

First off, write
4 ln 3 as:
\[\ln ^{\frac{ 3 }{ 4 }}\]

Answer 16

what are you talking about? that's wrong...

Answer 17

No.

Answer 18

it is41 times n to the power of 3...

Answer 19

These are LOGARITHMS

Answer 20

yea they are

Answer 21

ooh well you wrote 1 not l....

Answer 22

okay, then i can help you again.

Answer 23

sorry my mistake its hard to read the book looked like a 1 lol

Answer 24

first of all @gary-jenkinson do you know how to do basic logarithms?

Answer 25

oh its not problem.

Answer 26

*no

Answer 27

Okay, so once you do that, you change the form of the equation using one of the basic properties of logs.


\[\ln \frac{ 9 }{ 3^{4} }\]

Answer 28

yep, then thats right @AtlasOfAtlantis do you wanna continue or should i explain?

Answer 29

atlas may aswell continue thanks tho

Answer 30

okay, have fun! lol:D

Answer 31

You know that three squared is nine, so that changes your equation to:
\[\ln \frac{ 1 }{ 9 }\]

Answer 32

yea is that it?

Answer 33

You can leave it as that or try -ln9.

Answer 34

thanks for your help

Answer 35

You're welcome ^.^

Answer 36

how do you work this out as im really thick lol

Answer 37

Ahh, sorry. Uhm... just use the basic properties of logs. If you're confused when you look at them ln is also \[\log_{e} \].