How would you solve this?
?
(2^3)^4(2)^4
\[(2^{3})^{4} (2)^{4}\] Heres a better pic
\[(2^{3\cdot4})(2)^4=(2^{12})(2)^4=2^{12+4}\]
Would it be 2^16 or do you leave it like that?
ye it's 2^16
@HomeZone You add exponents not multiply them
PEMDAS
So first you add the 3 to the first 4?
\[(8)^4(2)^4\] \[(4096)(16)\]
\[(a^m)^n=a^{m\cdot n}\]
and \[(a^m)(a^n)=a^{m+n}\]
Here are my answers if it helps. A. 2^24 B. 2^9 C. 2^10 D. 2^13
I know how to do regular exponents but this question kinda threw me off a little.
None of those answers are correct I just typed the entire function into my calculator and it came out to 65,536
...ok. Well is there a different way to solve this kind of exponent?
Ye thats what im saying \[2^16=65536\]
Typeo* \[2^{16}=65536\]
The question says: Write as a power of 2
But that is not an answer... and it isn't a choice
wellll im just gonna call my regular instructor. This is for a practice test for a test im taking so im sure she could help me.
None of the aswers you're given are correct, the only way yo write 65536 to the power of 2 is 2^16
Answers*
ok well im gonna call and if u want I can let you guys kno what she says and how to solve it.
Alright first things first, there was a typo and the question says: Write as the power of 2: \[(2^{3})^{2}(2)^{4}\] so there is no first 4. Sorry about that. Now she solved it like this. First you multiply the 3 by the exp 2 to get 6 = 2^6 Then you say that there is an invisible 1 by the second 2. 1 x 4 is 4 leaving us with = 2^4. So now we have 2^6 2^4 and we solve and finish by using addition on the exponents. This gives the answer 2^10. :)
@HomeZone @AEYES13
Correct :) \[(2^{3⋅2})(2)^4=(2^6)(2)^4=2^{10}\] A typeo in math can do a lot for the end result :)
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