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Prove that n^2 + 5n is divisible by 2 where n is in N.
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\[n^{2}+5n\] is divisible by 2 where \[n \in N\]
hint : mathematical induction
Yeah I know mathematical induction, but that does not help.
well it does. we first check for n=1 for example and see that it works since 6/2 = 3. now we assume that it works for n=k so that k^2+5k is divisible by 2 now we check what happens with k+1 : (k+1)^2 + 5(k+1) is it divisible by 2 (assuming k^2+5k is) ?
and use the fact that even + even = even :)
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Multiply some and see if you can use what coolsector and hartnn said. Like look for k^2+5k. Look to use what you assumed before doing the induction step.
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