AP CHEM HELP. How much NaCl should be added to 0.35 L of a 0.15 M solution of AgNO3 so that it reacts completely with the silver to form AgCl(s)? A. 8.8 g B. 3.07 g C. 0.0525 g D. 0.89 mg
is it C?
how many MOLES of Ag+ ions are present in 0.35L of 0.15M solution?
1 mole
not even close. you're given a volume and concentration of a solution, how do you find moles given those two?
multiply it so 0.0525 moles
ok, now what's the mole ratio of Ag+ to Cl- ions when making silver chloride?
1:1
good. so that means 0.0525 moles of silver will require the same number of moles of chloride ions. What MASS of sodium chloride contains that many moles of Cl-1 ions?
35.45g
of CI- in 1 mole NaCl
but it's mass of sodium chloride, not just chloride ions.
1 mole of sodium chloride is 58.5g, but you don't need that much, you only need 0.0525 moles
im not sure how to figure that out
it's a ratio of units \[0.0525 \cancel{moles} * (\frac{58.5g}{1 \cancel{mole}})\]
3.07
unit?
grams
grams
ok, so the answer is 3.07 grams.
it is
Thanks!
yw
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