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Chemistry 7 Online
OpenStudy (anonymous):

AP CHEM HELP. How much NaCl should be added to 0.35 L of a 0.15 M solution of AgNO3 so that it reacts completely with the silver to form AgCl(s)? A. 8.8 g B. 3.07 g C. 0.0525 g D. 0.89 mg

OpenStudy (anonymous):

is it C?

OpenStudy (jfraser):

how many MOLES of Ag+ ions are present in 0.35L of 0.15M solution?

OpenStudy (anonymous):

1 mole

OpenStudy (jfraser):

not even close. you're given a volume and concentration of a solution, how do you find moles given those two?

OpenStudy (anonymous):

multiply it so 0.0525 moles

OpenStudy (jfraser):

ok, now what's the mole ratio of Ag+ to Cl- ions when making silver chloride?

OpenStudy (anonymous):

1:1

OpenStudy (jfraser):

good. so that means 0.0525 moles of silver will require the same number of moles of chloride ions. What MASS of sodium chloride contains that many moles of Cl-1 ions?

OpenStudy (anonymous):

35.45g

OpenStudy (anonymous):

of CI- in 1 mole NaCl

OpenStudy (jfraser):

but it's mass of sodium chloride, not just chloride ions.

OpenStudy (jfraser):

1 mole of sodium chloride is 58.5g, but you don't need that much, you only need 0.0525 moles

OpenStudy (anonymous):

im not sure how to figure that out

OpenStudy (jfraser):

it's a ratio of units \[0.0525 \cancel{moles} * (\frac{58.5g}{1 \cancel{mole}})\]

OpenStudy (anonymous):

3.07

OpenStudy (jfraser):

unit?

OpenStudy (anonymous):

grams

OpenStudy (jfraser):

grams

OpenStudy (anonymous):

ok, so the answer is 3.07 grams.

OpenStudy (jfraser):

it is

OpenStudy (anonymous):

Thanks!

OpenStudy (jfraser):

yw

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