I have a fill in the answer question for my study guide and I'd rather know how to figure this out now before the test.
For f(x) = 1/x^2 - 3 find f(3) and f(2+h)

I got f(3) I think, I just plugged in 3 for x but I'm confused how to get f(2 + h) it's a bit more confusing to me.

Thank you for any help :)

Question

I have a fill in the answer question for my study guide and I'd rather know how to figure this out now before the test. 
For f(x) = 1/x^2 - 3 find f(3) and f(2+h)

I got f(3) I think, I just plugged in 3 for x but I'm confused how to get f(2 + h) it's a bit more confusing to me. 

Thank you for any help :)

anonymous · Answer

Did they give you any more information?

anonymous · Answer

No that's not that bad:
$$f(x)=\frac{1}{x^2}$$
So then, $f(2+h)$ would be $f(x)$ but putting $2+h$ everywhere x is:
$$f(2+h)=\frac{1}{(2+h)^2}=\frac{1}{h^2+4x+4}$$