Find the average rate of change of f(x)= 7x^2+30
@agent0smith @amistre64
please anyone just need a step by step
hmm... ok, so do you know where to start off?
no can you help me @Clalgee can you do it step by step so i can take notes and do my other simmilair question?
@nincompoop can you help me?
The Average Rate of Change function describes the average rate at which one quanity is changing with respect to something else changing.
can you show me step by step so i can do the other one by myself?
In general, an average rate a change function is a process that calculates the the amount of change in one item divided by the corresponding amount of change in another. Using function notation, we can define the Average rate of Change of a function f from a to x as \[A(x)=\frac{ f(x)-f(a) }{ x-a }\]
A is the name of this average rate of change function x - a represents the change in the input of the function f f(x) - f(a) represents the change in the function f as the input changes from a to x a few examples to start: Find the slope of the line going through the curve as x changes from 3 to 0. Step 1: f (3) = -1 and f (0) = -4 Step 2: Use the slope formula to create the ratio \[\frac{ f(0)-f(3) }{ 0-3 }\] Step 3: Simplify. \[\frac{ f(0)-f(3) }{ 0-3 }=\frac{ -4-(-1) }{ 0-3 }=1\] Step 4: So the slope of the line going through the curve as x changes from 3 to 0 is 1.
ohh okay so would the rate of change be increasing or decreasing?
sec...
fo can you tell me where my 7x^2 and 30 fit into the formula?
had to get my graphing calc
in your question do they state x=? and x=?
find the AROC of (7x^2)+30 from x= something to x= something
let me show you my question i have graph also
that is a weird question for sure
yes i dont understadn it i have the graph i need to find the rate of change and see if its increasing or decreasing
let me find my old book and see what it says brb
so i think they want you to use the above formula, and substitute x values
for instance when x= -0.5 and x=1
that will give you an AROC
\[AROC= \frac{ f(-0.5)-f(1) }{ (-0.5)-1() }\]
f(-0.5)= 7((-0.5)^2)+30 = and f(1)= 7((1)^2)+30 =
\[\frac{ f(-0.5)-f(1) }{ -0.5-1 }=\frac{31.75-37 }{ -0.5-1 }=\frac{ -5.25 }{-1.5 }\]
AROC = 3.5
increasing with justification :)
you can try it again with any other x values, for practice, then substitute into your equation
oh k tahnks :)
np
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