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Mathematics 17 Online
OpenStudy (anonymous):

I Only Have This Problem I Will Medal And Fan You Solve the inequality. 3 + |t + 4| < 10

OpenStudy (anonymous):

−11<t<3

OpenStudy (anonymous):

ty @vivianx333 <3

OpenStudy (anonymous):

no problem :)

OpenStudy (anonymous):

im not really a lesbian btw

OpenStudy (anonymous):

for this problem, you have two cases, one where (t+4)>0, and one where (t+4)<0. In case one, your parameter, if you solve (t+4)>0 for t is t must be greater than -4. The is the easy case, because |t+4| is just equal to t+4, since it is positive. So, your euqation for case 1 becomes 3+t+4<10, which becomes -1-t<10 which becomes -1-10<t, which becomes -11<t. Remember than your original parameter was that t>-4. Because there is no value of t that is greater than -4 and also be less than -11, this is not a solution to the problem. To check for another solution, you have to do the same with case 2. your parameter for case 2 is that t<-4, and because (t+4)<0. |t+4| is equal to -(t+4). (remember than an abolute value sign is both the postive and the negative of the number.) so, solve your equation 3 + -(t+4)< 10. If the answer you come to fits your parameter, you have your solution.

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