Question

^3 radical 64a^16

Answer 1

the answer is









































i dont know it CX sorry

Answer 2

?

Answer 3

i was trolling -_-

Answer 4

hey ! who deleted my comment here ?

Answer 5

Do you mean \(\sqrt[3]{64a^{16}}\) ?

Answer 6

Look at 64 and write is as a prime number raised to a power.

Answer 7

\(\sqrt[3]{64a^{16}} \)

\(= \sqrt{2^{6} \times a^{16}} \)

Now keep in mind that the third power, cube, and cubic root are opposites.

Answer 8

i do not know of this....WIZARDRY!!!

Answer 9

Since cubing and taking the cubic root are opposites, you get this.
\( \sqrt{a^3} = a\)

Back to your problem:

\(\sqrt{64 a^{16}} \)


\(=\sqrt{2^6 \times a^{16}} \)


\(=\sqrt{2^3 \times 2^3 \times a^3 \times a^3 \times a^3 \times a^3 \times a^3 \times a} \)

\(= 2 \times 2 \times a \times a \times a \times a \times a \times \sqrt{a} \)

\(= 4a^5 \sqrt{a} \)

Answer 10

im clueless...

Answer 11

im only in 7th grade