Question

0.901g KHP is titrated with 44.1 mL of unknown NaOH solution. What is the concentration of the NaOH solution?
My solution was .1M using c=mol/volume but is this correct?
It seems to simple.

Answer 1

did they give you a balanced equation?

Answer 2

No

Answer 3

But I believe its a one to one ratio

Answer 4

KHP is potassium hydrogen pthalate \(C_8H_5KO_4\)

Answer 5

so you ca write the equation yourself

Answer 6

KHP+ NaOH --> KNaP + H2O
Correct thats the formula

Answer 7

KHC8H4O4(aq) + NaOH(aq) --> KNaC8H4O4(aq) + H2O(l)

Answer 8

use stoichiometry

Answer 9

I keep getting 0.1 M

Answer 10

Is that correct?

Answer 11

no, i'm getting something completely different

Answer 12

moles of KHP were 4.41*10^-3
so what I did was
4.41*10^-3*1000ml /(44.1ml)=0.1M
where did I go wrong?

Answer 13

How did you get the moles of KHP?

Answer 14

.901 g are given and the molar mass is 204.227g/mol
so I divided them
to get 4.41*10^-3

Answer 15

those are the right moles, but for NaOH, through stoichiometry with the balanced equation.

Answer 16

Then take those moles and the volume they gave you converted to L, and plug them into the equation M=mol/L or c=mol/volume in L.

Answer 17

this for the NaOH, like they asked.

Answer 18

Isnt this in equilibrium? So shouldnt moles of KHP = Moles of NaOH?
Let me give it another try.
Thank you