Mathematics
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OpenStudy (ams98):
Explain these to me so I don't get the same type question wrong again!!! Complex Numbers! MEDAL!!
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OpenStudy (ams98):
@GABI_J
OpenStudy (ams98):
(−3 + 2i) • (2 + i)
OpenStudy (ams98):
What do you mean??
OpenStudy (cggurumanjunath):
FOIL METHOD.
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OpenStudy (ciel21):
if i explain 9/10 chances i wont get a medal :'c
OpenStudy (anonymous):
Yes, Foil.
\[(a+b)(c+d)\]
\[ac+ad+bd+bc\]
OpenStudy (ams98):
Okay let me try one sec!
OpenStudy (anonymous):
\[(−3 + 2i) • (2 + i)\]
Recalling)
OpenStudy (ams98):
Oh gawsh i still probably got it wrong as I suck at math but I got -8-i
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OpenStudy (anonymous):
Almost, look over your work again!
OpenStudy (anonymous):
One part is wrong the other is right?
Which one is wrong -8 or
-i
what do you think?
OpenStudy (ams98):
-8+i??
OpenStudy (ams98):
I did wrong signs
OpenStudy (anonymous):
Yes,
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OpenStudy (anonymous):
you are right now
OpenStudy (ams98):
Okay one more! And thanks so much!!
OpenStudy (anonymous):
Ask away!
OpenStudy (ams98):
(1 + 2i) • (5 − 3i)
OpenStudy (ams98):
let me try... :)
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OpenStudy (anonymous):
you can do it!
OpenStudy (ams98):
11+7i?
OpenStudy (anonymous):
Yes!
OpenStudy (anonymous):
Can I give you a harder example?
OpenStudy (ams98):
Ahh thanks so much! Your a life saver!!
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OpenStudy (ams98):
and sure!
OpenStudy (anonymous):
OK, ready?
\[\frac{5+i}{2-i}\]
This is also trig, but a little harder
Hint to think_ you can have a radical in a denominator
Any ideas?
OpenStudy (ams98):
hmmm give me a hint!
OpenStudy (anonymous):
Multiply the equation by \[\frac{2+i}{2+i}\].
this is what I refer to as a magical 1.
OpenStudy (anonymous):
I'll right it out for you, and you multiply, Ok?
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OpenStudy (ams98):
always? OK
OpenStudy (anonymous):
\[\frac{(5+i)(2+i)}{(2-i)(2+i)}\]
Right? Do this one for me real quick.
OpenStudy (ams98):
What do you do with the I's? Sqaure them? But if you square them arent they just like a -1?
OpenStudy (anonymous):
i^2 is exactly -1
OpenStudy (anonymous):
So write it out for me please....
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OpenStudy (ams98):
Okay! So I am ushally wrong but....\[\frac{ 10-1 }{ 4-1 }=\frac{ 9 }{ 3 }= 3\]
OpenStudy (anonymous):
No, ain't right!
OpenStudy (anonymous):
You forgot about the middle term on top!
OpenStudy (anonymous):
\[(5+i)(2+i)\] what is the middle term?
OpenStudy (ams98):
Im lost!! I try re-doing it and I got something like this :(\[\frac{ 9+10i }{ 3+0 }\]
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OpenStudy (anonymous):
Nope!
OpenStudy (anonymous):
9 is right, what is wrong?
OpenStudy (anonymous):
You got confused it is not 2*5i
it is 2i+5i
Don't you see that?
OpenStudy (anonymous):
\[(a+b)(c+d)_\]
\[a(c+d)+b(c+d)_\]
\[ac+ad+bc+bd_\]
OpenStudy (ams98):
wait so just 10 lmao?
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OpenStudy (anonymous):
No, it is 9+7i
b/c the number of i s is 2+5
see (I mean if you foil, step by step)
OpenStudy (ams98):
geeez I'm terrible at math xD
OpenStudy (anonymous):
Do you understand?
OpenStudy (anonymous):
\[Understand?\]
OpenStudy (ams98):
kind of sort of!