A small solid sphere and a small thin hoop are rolling along a horizontal surface with the same translational speed when they encounter a 20 ∘ rising slope.
Part A

If these two objects roll up the slope without slipping, which will rise farther up the slope?
The sphere.
The hoop.
Both the same.
More information about the objects' mass and diameter is needed.

Question

A small solid sphere and a small thin hoop are rolling along a horizontal surface with the same translational speed when they encounter a 20 ∘ rising slope.
Part A

If these two objects roll up the slope without slipping, which will rise farther up the slope?
	 The sphere.
	 The hoop.
	 Both the same.
	 More information about the objects' mass and diameter is needed.

anonymous · Answer

@Loser66 can you please help me

anonymous · Answer

how can i figure this out without numbers? i am not sure but I think that we will need the mass to find it out

loser66 · Answer

I will choose "Both the same"

anonymous · Answer

how is that possible? i dont undetstand this can you please explain a little

loser66 · Answer

the gravitational force are the same to anything. a 60kg ball and a feather will hit the ground at the same time if we release them at the same height. In this case , they roll down on the same inclined plane. So, the result must be the same.

loser66 · Answer

@agent0smith  help me, friend. how to put everything in logic? I don't know

anonymous · Answer

in the book i was looking at some formulas, comparing hollow and non hollow

agent0smith · Answer

Rolling w/o slipping means there is friction - and this means the type of shape matters. It depends on its moment of inertia, as to how far it'll roll. I don't remember what the moment of inertia looks like for a sphere vs a hoop, or really how to decide which one decelerates faster.

anonymous · Answer

2/5MR^2 is a uniform sphere, MR^2 is the thin hoop ...i was thinking that the mass and radius would matter just by looking that these, but  i dont know either