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Mathematics 20 Online
OpenStudy (anonymous):

assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt dx/dt when x=4 dx/dt=3

OpenStudy (anonymous):

$$\frac{dx}{dt} = 3 \\ dx = 3 dt \\ \int dx = \int 3 dt = 3t$$ Where do you go from here?

OpenStudy (anonymous):

I forgot to say that the function is the square root of x

OpenStudy (anonymous):

Which function?

zepdrix (zepdrix):

\[\Large x=x(t)\]\[\Large y=y(t)\] \[\Large y=\sqrt x\] I don't quite understand your question. Is this what you meant to write? `Find dy/dt when x=4 and dx/dt=3`

OpenStudy (anonymous):

Yes using the square root of x I got that dy/dt= 3/4

zepdrix (zepdrix):

Hmm yes that's what I'm coming with also. Good job! :)\[\Large \frac{dy}{dt}\quad=\quad \frac{1}{2\sqrt x}\frac{dx}{dt}\]Plugging in the values appears to give us 3/4!

OpenStudy (goformit100):

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