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OCW Scholar - Physics I: Classical Mechanics 6 Online
OpenStudy (anonymous):

A 49.3-g golf ball is driven from the tee with Vi of 53.3 m/s rises to hight of 28.2m. (a) neglect resistance and determine the KE at its highest point. (b) what is the speed when it is 7.31m below its highest point? A)________(j) B)49.3 m/s What is answer for A?

OpenStudy (anonymous):

since no air resistance vi=vpeak=vfinal in the x direction, so then to find KE of peak you would use .5*m*vi^2=KE note that this kinetic E remains constant in x direction until you add some sort of friction or air resistance to stop it, your potential energy will change because its in the y-direction. I may be wrong but this is how I would have approached it

OpenStudy (anonymous):

the equation is 1/2mv squared.....all u need to do is plug the numbers in and get the answer...which is 2840.89 multiplied by 24.65

OpenStudy (anonymous):

WHOOPS...i forgot that it was KG not G...so it's 2840.89 multiplied by 0.02465...which is 70.0279385

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