A 49.3-g golf ball is driven from the tee with Vi of 53.3 m/s rises to hight of 28.2m. (a) neglect resistance and determine the KE at its highest point. (b) what is the speed when it is 7.31m below its highest point? A)________(j) B)49.3 m/s What is answer for A?
since no air resistance vi=vpeak=vfinal in the x direction, so then to find KE of peak you would use .5*m*vi^2=KE note that this kinetic E remains constant in x direction until you add some sort of friction or air resistance to stop it, your potential energy will change because its in the y-direction. I may be wrong but this is how I would have approached it
the equation is 1/2mv squared.....all u need to do is plug the numbers in and get the answer...which is 2840.89 multiplied by 24.65
WHOOPS...i forgot that it was KG not G...so it's 2840.89 multiplied by 0.02465...which is 70.0279385
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