simplifying completely
\[\frac{ z ^{3}-4z }{z ^{2}-4z+4 }\] top one is, z^3 bottom one is , z^2
Have you considered factoring completely both the numerator and the denominator?
im not sure how to factor the top but the bottom one is (z-2)(z-2)
@tkhunny
What course is this? \(z^{3} - 4z = z(z^{2} - 4)\) -- More to do?
algebra2 and okay i see where your going. but would it be possible to do z(z^2-2)(z+2)
You should recognize the difference of squares. \(z^{3} - z = z(z^{2} - 4) = z(z+2)(z-2)\)
so. \[\frac{z (z+2)(z-2) }{ (z-2)(z-2) }\] then cancel out both (z-2) on top and bottom. then it becomes \[\frac{ z(z+2) }{ (z-2) }\]
That's about it. Note: Change your screen name. What chance do you have to succeed if that's how you advertise yourself?!
haha! okay i will.:D thank you so much for your help
You did well. Hang in there!
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