simplifying completely

Question

anonymous · Answer

$$\frac{ z ^{3}-4z }{z ^{2}-4z+4 }$$
top one is, z^3
bottom one is , z^2

tkhunny · Answer

Have you considered factoring completely both the numerator and the denominator?

anonymous · Answer

im not sure how to factor the top but the bottom one is (z-2)(z-2)

anonymous · Answer

@tkhunny

tkhunny · Answer

What course is this?

$z^{3} - 4z = z(z^{2} - 4)$ -- More to do?

anonymous · Answer

algebra2
and okay i see where your going. but would it be possible to do z(z^2-2)(z+2)

tkhunny · Answer

You should recognize the difference of squares.

$z^{3} - z = z(z^{2} - 4) = z(z+2)(z-2)$

anonymous · Answer

so. $$\frac{z (z+2)(z-2) }{ (z-2)(z-2) }$$
then cancel out both (z-2) on top and bottom.
then it becomes $$\frac{ z(z+2) }{ (z-2) }$$

tkhunny · Answer

That's about it.

Note: Change your screen name.  What chance do you have to succeed if that's how you advertise yourself?!

anonymous · Answer

haha! okay i will.:D thank you so much for your help

tkhunny · Answer

You did well.  Hang in there!