When I'm using limits to determine whether or not a function is continuous and it turns out it's removable discontinuity, what would the values look like?
For example, when it's jump discontinuity, the values of each one sided limit are different, but what would the limits of removable discontinuity look like? the same? finite?
The values would not hold a geometric ratio with the rest of the function. For instance, in a parabolic function that is discontinuous at point 2: x = 0, y = 0^2 = 0 x = 1, y = 1^2 = 1 x = 1.5, y = 9/4 x = 1.999, y = 3.996001 x = 2, y = 0
I mean, when you are finding right hand and left hand limits, do they equal each other? Are they finite?
I still don't get it.....
It is a general limit, so yes. "Right hand" and "left hand" limits are equivalent.
but then how would I know if it's a discontinuity!? Or if it's removable!?
If the limit as x->c for f(x) is not equal to f(c).
so in other words, the left and right hand limits are equal, so the general limit exists, but it's not continuous because limit as x-->c for f(x) is not equal to f(c) and f(c)?
Or rather, let me put it more precisely. Let's say we have this function: $$f(x) = \begin{cases} x^2 & x \not = 2\\ 0 & x = 2 \end{cases}$$ f(2) is not equal to 2^2, so the limit is not equal to what the function actually is. You are correct.
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