Question

x-3=-3x+13

Answer 1

I got 4, Right?

Answer 2

Yes.

Answer 3

Thank You!

Answer 4

That was the worse joke I ever made! Sorry guys!

Answer 5

What!!! you set up a question and get a response Imposssibruuuuu , i have been waiting for hours.

Answer 6

Dude tag me I am good at Trig and below.

Answer 7

Did that work lol?

Answer 8

Is it literature then (American, European, Russian)
English? I am a senior.....
I got tagged, Bye!

Answer 9

Did I? it says I got tagged I did not!

Answer 10

No more jokes a serious problem, OK?

Answer 11

LOL i tagged you.

Answer 12

Do you guys have any questions what so ever! Tag me please I can help you anytime!!!!!!!!!!!!

Answer 13

Here, @SolomonZelman:
$$A = \begin{pmatrix} 3 & 0 & -i \\ 0 & 3 & 0 \\ i & 0 & 3 \end{pmatrix}$$
A is a 3 by 3 Hermitian matrix, so it has real eigenvectors and eigenvalues \(|\phi_0 \rangle, |\phi_1 \rangle,|\phi_{2} \rangle \) and \(\lambda_0, \lambda_1, \lambda_2\):
$$\vec \phi_0 = \langle i, 0, 1 \rangle ; \lambda_0 = 2 \\ \vec \phi_1 = \langle 0, 1, 0 \rangle; \lambda_1 = 3 \\ \vec \phi_2 = \langle -i, 0, 1 \rangle; \lambda_2 = 4$$
I'm asked to transform the coefficients of the basis states in a state \(|\psi (t) \rangle\), by multiplying by \(e^{-i \lambda_j t}\), where \(t\) is a number. \( |\psi(0) \rangle = |0 \rangle\). This is simple, but my problem is I can't rewrite the \(|0 \rangle\) state as a linear combination of the three eigenstates. When attempting to solve it normally, I get:
$$|0 \rangle = -\frac{i}{\sqrt{2}} |\phi_0 \rangle + \frac{i}{\sqrt{2}} |\phi_2 \rangle $$ or $$\langle 1, 0 \rangle = \langle -\frac{i}{\sqrt{2}}, 0, \frac{i}{\sqrt{2}} \rangle$$
When transforming both coefficients by the exponentation function mentioned above when $t=\pi$:
$$|0 \rangle = -\frac{i}{\sqrt{2}} |\phi_0 \rangle - \frac{i}{\sqrt{2}} |\phi_2 \rangle $$ or $$\vec 0(t) = \langle -\frac{i}{\sqrt{2}}, 0, -\frac{i}{\sqrt{2}} \rangle$$
I then rewrite in the 0, 1, 2 basis:
$$-i |2 \rangle$$ or \((langle 0, 0, -i \rangle\).
This is obviously wrong. The correct answer is \(-|0 \rangle\). Where am I going wrong?

Answer 14

Didn't I say trig and below. Sorry i don't know that staff!
Are you 19?

Answer 15

You knew I don't know it..... I mean 16yr old guy isn't supposed to know.....
My bad again, i have no clue about what Hermitian matrix is.