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Mathematics 19 Online
OpenStudy (lena772):

Evaluate (if possible) the function at the given value(s) of the independent variable. Simplify the results. f(x)=x+3/x+1 f(x)-f(1)/x-1

OpenStudy (lena772):

OpenStudy (lena772):

@ganeshie8

ganeshie8 (ganeshie8):

that red circled one ?

OpenStudy (lena772):

Yes :)

ganeshie8 (ganeshie8):

you're given, \(\large f(x) = x^3-x\)

ganeshie8 (ganeshie8):

and asked to evaluate, \(\large \frac{f(x)-f(1)}{x-1}\)

ganeshie8 (ganeshie8):

start by finding \(f(1)\)

ganeshie8 (ganeshie8):

then plug that value in the expression you wanto evaluate

OpenStudy (lena772):

f(1)=1^3-1 f(1)=0?

ganeshie8 (ganeshie8):

Excellent !

OpenStudy (lena772):

:)

ganeshie8 (ganeshie8):

plug that value in the given expression

OpenStudy (lena772):

f(x)-0/x-1 f(x)/x-1

ganeshie8 (ganeshie8):

plug f(x) value also, and simplify

ganeshie8 (ganeshie8):

\(\large \frac{f(x)}{x-1}\) \(\large \frac{x^3-x}{x-1}\)

ganeshie8 (ganeshie8):

simplify

OpenStudy (lena772):

I don't know how to simplify that

ganeshie8 (ganeshie8):

factor top and see if u can cancel out something

ganeshie8 (ganeshie8):

\(\large \frac{f(x)}{x-1}\) \(\large \frac{x^3-x}{x-1}\) \(\large \frac{x(x^2-1)}{x-1}\) \(\large \frac{x(x+1)(x-1)}{x-1}\)

OpenStudy (lena772):

x(x+1)?

OpenStudy (lena772):

which would be x^2+x ?

ganeshie8 (ganeshie8):

\(\large \color{red}{\checkmark}\)

OpenStudy (lena772):

so all i have to write for my answer is x^2+x?

ganeshie8 (ganeshie8):

yup, that will do

OpenStudy (lena772):

can you help me with another?

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