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Mathematics 22 Online
OpenStudy (anonymous):

e^2x-1 + 5 =8

OpenStudy (anonymous):

first step, simplify the expression, so move all the 'like' terms to the same side of the equation

OpenStudy (anonymous):

is it e^(2x)-1 + 5 or e^(2x-1) + 5

OpenStudy (anonymous):

?

OpenStudy (anonymous):

the second one

OpenStudy (anonymous):

great, e^(2x-1) + 5 = 8, we need to simplify the expression by combining all the 'like' terms, post up what you get

OpenStudy (anonymous):

i think i did it wrong but lne^(2x-1) =ln3

OpenStudy (anonymous):

close, we do want to use ln, but we want to use the 'definition of logs' to get the x out of the exponent's place. are you familiar with the 'definition of logs'?

OpenStudy (anonymous):

\[e^{n} = m \rightarrow \ln(m) = n\]

zepdrix (zepdrix):

Yah that method works fine Ms Teisha :) \[\Large \ln e^{(2x-1)}\quad=\quad(2x-1)\ln e\quad=\quad (2x-1)\cdot1\]So that's how your left side would simplify. It's a little bit more cumbersome than simply remembering how to rewrite something in log form as Demolish demonstrated, but still works fine.

OpenStudy (anonymous):

so take your equation: e^(2x-1) =3 and apply this rule that looks like this: \[e^{n}=m→\ln(m)=n\] so pick out what terms in your equation looks like the 'n' and the 'm'

OpenStudy (anonymous):

I have no idea!. . . . .

OpenStudy (anonymous):

If I said n = (2x-1) can you pick out m = ?

OpenStudy (anonymous):

do you see how they are similar? the 'form' and your equation?

OpenStudy (anonymous):

so is it in ( 3) = 2x-1 ???

OpenStudy (anonymous):

yep! just don't forget the ln, so like this: ln(3) = 2x-1 now isolate the x, or in other words, get all the 'non' x numbers to the opposite side of x.

OpenStudy (anonymous):

first move the 1 over to the other side

OpenStudy (anonymous):

is x 2?

OpenStudy (anonymous):

ya so now it looks like this: ln(3) + 1 = 2x then just divide both sides by 2

OpenStudy (anonymous):

so 2 right?

OpenStudy (anonymous):

ya, so what now our equation looks like this: x= ( ln(3) + 1 ) / 2

OpenStudy (anonymous):

Is that the final answer?

OpenStudy (anonymous):

yep, good job!

OpenStudy (anonymous):

good job to you. I didn't do anything lmao

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