How many ways are there to rearrange the letters in the word aptitude, if the first and last letter must each be a vowel?
I know I have to calculate how many letters to choose from. then multiply them by each other for each spot right?
5*26^6**5
right?
lets make it easier and say the first two letters have to be vowels (clearly makes no difference) then4 choices for the first 3 for the second then you have 6 letters left the number of ways to arrange 6 letters if they are all different is \(6!=6\times 5\times 4\times 3\times 2\) but since you cannot tell the two "t" s apart, it is \(\frac{6!}{2}=6\times 5\times 4\times 3\)
yuuup I was wrong
multiply all this mess together to get your answer
doing so now
450? but I don't think that's right. working in my head not good.
360.
you have yet to multiply all the numbers satellite73 gave to you
yup im lost
4*3*6*5*4*3
4320
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