How many ways are there to rearrange the letters in the word aptitude, if the first and last letter must each be a vowel?
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OpenStudy (anonymous):
I know I have to calculate how many letters to choose from. then multiply them by each other for each spot right?
OpenStudy (anonymous):
5*26^6**5
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
lets make it easier and say the first two letters have to be vowels (clearly makes no difference)
then4 choices for the first
3 for the second
then you have 6 letters left
the number of ways to arrange 6 letters if they are all different is \(6!=6\times 5\times 4\times 3\times 2\) but since you cannot tell the two "t" s apart, it is \(\frac{6!}{2}=6\times 5\times 4\times 3\)
OpenStudy (anonymous):
yuuup I was wrong
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OpenStudy (anonymous):
multiply all this mess together to get your answer
OpenStudy (anonymous):
doing so now
OpenStudy (anonymous):
450? but I don't think that's right. working in my head not good.
OpenStudy (anonymous):
360.
OpenStudy (zarkon):
you have yet to multiply all the numbers satellite73 gave to you
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