A wire carries a 1.7A current for 10s . How many electrons move past a point in the wire? Ne=?
I have tried this, I feel my math is correct, any other ideas.

Question

A wire carries a 1.7A current for 10s . How many electrons move past a point in the wire? Ne=?  
I have tried this, I feel my math is correct, any other ideas.

doc.brown · Answer

$$A = \frac{6.241\times 10^{18}electrons}{second}$$$$1.7\times\frac{6.241\times 10^{18}e}{s}\times 10s$$$$=1.1\times 10^{20}e$$

doc.brown · Answer

@ GopZ Q is electric charge.

anonymous · Answer

@doc, yeah m aware of that, q=I.t ryt?

anonymous · Answer

Q=I.t
  =10*1,7
  =17

Ne=17/1,6*10^-19
    =1,1*10^20 electrons

@doc, my mistake, thanks! #wink

doc.brown · Answer

Cool