Question

A wire carries a 1.7A current for 10s . How many electrons move past a point in the wire? Ne=?
I have tried this, I feel my math is correct, any other ideas.

Answer 1

\[A = \frac{6.241\times 10^{18}electrons}{second}\]\[1.7\times\frac{6.241\times 10^{18}e}{s}\times 10s\]\[=1.1\times 10^{20}e\]

Answer 2

@ GopZ Q is electric charge.

Answer 3

@doc, yeah m aware of that, q=I.t ryt?

Answer 4

Q=I.t
=10*1,7
=17

Ne=17/1,6*10^-19
=1,1*10^20 electrons

@doc, my mistake, thanks! #wink

Answer 5

Cool