0 = 4x^2 - 8x - 5
Do you know the quadratic formula?
\[\frac{ -(b) \pm \sqrt{(b)^{2}-(4)(a)(c)}}{ 2(a) }\]
yes, ive seen it, need help though
Where are you stuck then? The Quadratic formula works perfectly for quadratic equations
help me through it, I don't know how to do this
Divide every number by "4" then plug the new equation you have into the quadratic formula. Tell me when you have done this.
k
-5 cant be divided by 4
why can't it be divided 4?
or is it a = 4, b = -8 , c = -5 ?
You can do it that way if you want, if you have a harder time working with fractions.
I do
what do I do now, substitute my a, b, c into the formula?
yes
\[8 + \sqrt{-8^2 - 4(4)(-5) / 2(4)
Okay. I think you were trying to write this: \[\frac{ 8 \pm \sqrt{(-8)^{2} - 4(4)(-5)} }{ 2(4) }\]
yes
Alright. now do the math and find your two real answers.
\[8+\sqrt{64 +40}/8\]
is the 40 negative or positive?
oops its 80
well the equation inside reads as so:\[(-8)^{2}-4(4)(-5)\] the second term will eventually become a negative and you're subtracting a negative. do you think it should be positive?
yes
good job. Now solve the rest of the math,
\[8+\sqrt{144/8}\]
do I have to divide?
the square root should only encompass the 144 not the division of 8 as that should be under the whole numerator as so:\[\frac{ 8 \pm \sqrt{144} }{ 8 }\] do the square root first then do the numerator first for the "+" then the "-" and divide your numerators by your denominator to get your two answers
sqrt 144 is is 12
20/4 = 5
20/8***
right
20/8 = 2.5
is that it?
okay good job. But remember we're trying to solve for the variable "x" so how can we show that it equals 2.5
don't know
2.5 = x?
Yes. Another way you can show it in factor form is (x-2.5) since we're trying to find two factors that equals your quadratic equation. Now solve for your second one.
so how can i find the second factor?
you did your "+" one where is your "-" from your quadratic solution? Remember you ended up at:\[\frac{ 8\pm \sqrt{144} }{ 8 }\]
oh so now i subtract 8 - 12?
yes. when you see this sign:\[\pm\]it means "add" AND "subtract" the two terms on the two sides
oh ok, so 8 - 12 is -4
then divide -4/8 = -0.5
Awesome. Now how would you represent that in factored form?
that's the second factor (x - 0.5) ( x + 2.5)
( x + 2.5) (x - 0.5)
i think this is the factored form
No. remember that quadratic equation equals to "0" so when we use the quadratic formula we find any numbers that would make the quadratic equation equal to "0" so with your first factor: 0 = (x - 2.5) which equals x = 2.5 since we moved the 2.5 to the other side by addition. we would also represent your second factor equaling to "0" since if we were to plug in the final number you received it would make the original quadratic equation "0" also. 0 = x + 0.5, we subtract 0.5 from each side to get x = -0.5 which was your answer right? so in factored form together these two will look like this \[0 = (x-2.5)(x+0.5)\]
Another way to remember this is to change the sign of the number you get as your final answer to the opposite sign when putting it in factored form: for example, if I were to get x = 5, and I want to put it into factored form. I would look at the number if it's either positive or negative. "5" here is positive so I changed it to negative so I can put it in factored form (x -5). This only applies when the quadratic equation is equal to "0"
oh i get it!!!! answer would be 0 = ( x -2.5) (x + 0.5) Is that all?
Yes. That is all. Good work.
thank you so much!!!!!!!! :)
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