how much 50% antifreeze solution and 40% antifreeze solution should be combined to give 50 gallons of 46% antifreeze solution?

Question

anonymous · Answer

your question is essentially: x*.5 + (1-x)*.4 = .46

x will represent the PROPORTION of 50% antifreeze and 1-x will represent the proportion of 40% antifreeze.

goformit100 · Answer

A warm Welcome to OpenStudy. I can help guide you through this useful site. You can ask your questions to me or you can message me. Please use the chat for off topic questions. Remember to give the person who helped you a medal by clicking on "Best Answer". We follow a code of conduct, ( http://openstudy.com/code-of-conduct ). Please take a moment to read it.

anonymous · Answer

so then the total amount is the proportion of each multiplied by 50

anonymous · Answer

follow the math: x*.5 + (1-x)*.4 = .46
distribute: .5x+.4 -.4x = .46
add: .1x +.4 = .46
.1x = .06
x= .6
so 60% of of the volume should be the 50% solution