Question

Find the point C such that AC and BC form a 2:3 ratio

Answer 1

(-1, 1.2)
(-0.6, 3)
(0, 2.4)
(0.5, 2)

Answer 2

@tester97 help

Answer 3

@Hero

Answer 4

@ganeshie8

Answer 5

notice the 2 poins given, ( -3, 5) and (3, 0)

use the distance equation to see how long the line AB is

\(\large {\text{distance between 2 points}\\
d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}}\)

Answer 6

ok... so you need

\[\frac{AC}{BC} = \frac{2}{3}\]

or 3AC = 2BC

so the points are A(-3, 5) and B(3, 0)

so you are looking at 3(-3, 5) and 2(3, 0)

so for x its \[3 \times -3 + 2 \times 3 = \]

then divide the answer by the sum of the parts in the ratio 2 + 3

same for y its \[3 \times 5 + 2 \times 0 =\]

then divide the answer by the sum of the parts in the ratio.