Question

dy/dx y^2=2yy'? i am pretty sure its that i just want to make sure.

Answer 1

\(\bf \textit{using the power rule}\\ \quad \\
\cfrac{dy}{dx}\quad y^\color{red}{2}\implies \color{red}{2}y^{\color{red}{2}-1}\)

Answer 2

i want the derivative with respect to x

Answer 3

ohh

Answer 4

do you know how to do that?

Answer 5

@jdoe0001 ?

Answer 6

no, don't think I know that one

Answer 7

oh ok

Answer 8

\[\frac{d}{dy} y^2=2y^{2-1}\]
\[\frac{d}{dx} y^2=2y^{2-1}y'\]
Why do you have\[ y' y^2=2yy'\]

Answer 9

i need the derivative with respect to x

Answer 10

The derivative of what?

Answer 11

y^2

Answer 12

I already gave that.

What you have is \[y'y^2=2yy'\]

Answer 13

so i am right

Answer 14

I think you mean to say dy^2/dx=2yy'

Answer 15

There is a difference.

Answer 16

ok got it thanks

Answer 17

and what would it be just for y

Answer 18

\[\frac{dy}{dx} =y'=f'(x)=\frac{df}{dx}=\frac{d}{dx} f(x)\]

Answer 19

\[\frac{d(y^2)}{dx}=2y^{2-1} \cdot \frac{dy}{dx}=2y \frac{dy}{dx}\]