Find the point on the graph of x+ y^2=0 that is closest to the point (0,-3).

Question

myininaya · Answer

Solve for x
Use the distance formula.
Use the following points to find the distance between (what you got when you solved for x , y) and (0,-3).

anonymous · Answer

what math do you take?

anonymous · Answer

$$d=\sqrt{(-y^2-0)^2+(y-3)^2}$$
this is what I did before, just wanted to make sure if I'm on the right  track, 
@myininaya sorry late response, i ate my dinner..

@Mr.ILikeToRead It's calcullus :)

myininaya · Answer

y+3?

myininaya · Answer

$$d=\sqrt{(-y^2-0)^2+(y+3)^2}=\sqrt{y^4+(y+3)^2}$$

myininaya · Answer

$$f(y)=y^4+(y+3)^2$$
Find f'(y).

anonymous · Answer

oh, yeah.. so that's what my mistake is!! thanks a lot!!
I really need to be careful >.<

myininaya · Answer

You are going to get a nasty equation to solve though.

anonymous · Answer

Don't worry I can manage it now ;p
I keep doing this but keep getting the wrong answer because of my stupid mistake >.>