cos θ - sin θ = √2 sin θ/2
must be between the interval \[[0,2\pi]\]
the directions say this, "Use a Double- or Half-Angle Formula to solve the equation in the interval [0,2pi]." The answers in the book say \[\pi/6,3\pi/2\]
\(\bf cos(\theta)-sin(\theta)=\cfrac{\sqrt{2}\quad sin(\theta)}{2}\quad ?\)
thats what it appears to be naturally just the line isn't there but yes thats the problem :)
I remember my professor telling me that in problems like this, to always do the side that looks more ocmplicated
One sec let me google search the half angle and double angle formulas
I tried dividing out the \[\sqrt{2}\] but that didnt help, and converting the sin in to a square root but it didnt help. Gotta love College Trig classes I like calculus better :)
the book says the answers are \[\pi/6,3\pi/2\]
I'm working it out right now
Sorry I'm taking so long I just seem to be having a hard time finding the half and souble angle formulas
i got them handy :) ill type them in
And are you sure it's not....
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