Question

y=square root of 2x+3

Answer 1

what about it?

Answer 2

what are you looking for?

Answer 3

how do u find the points of discontinuity and the type of discontinuity

Answer 4

y = \[y = \sqrt{2x + 3}, y = \sqrt{2x} + 3\]
which one is it?

Answer 5

the former

Answer 6

the points of discontinuity are found by finding out what x value makes the equation undefined.

Answer 7

is there no fraction?

Answer 8

no fraction, no

Answer 9

hm..

Answer 10

I know how to do most of like the other problems but with the square root I'm getting kind of thrown off

Answer 11

There is no fraction, so i don't think there is any value that would make this undefined..

Answer 12

all points in the domain i.e., all x<-3/2

Answer 13

that's the global minimum

Answer 14

as well

Answer 15

but the fraction is just
\[y = \frac{ \sqrt{2x+3} }{ 1 }\]

Answer 16

so basically as long as the number in the root isn't less than 0 it's fine?

Answer 17

Pretty much yes, you cant have something like √-25

Answer 18

You only want real numbers ...

Answer 19

\[inside \ge 0\]

Answer 20

Is this a continuous function?

Answer 21

I don't think so. The point of discontinuity would be (-3/2, 0) because all real numbers except at that value.

Answer 22

ok thanks