if the length of a rectangle is x+6 and width is x-2. Find the value of x that would allow the rectangle to have a maximum area.
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OpenStudy (superhelp101):
@robtobey PLZZZZ help
OpenStudy (superhelp101):
@texaschic101 plzzzzz help!!
OpenStudy (superhelp101):
@zepdrix
OpenStudy (superhelp101):
Can you plzz help me? :((
zepdrix (zepdrix):
The rectangle which has the largest area is one in which the length is the same as the width. In other words, a square! :)
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OpenStudy (superhelp101):
ok..
zepdrix (zepdrix):
|dw:1382574543091:dw|So these side lengths are equal\[\Large x+6\quad=\quad x-2\]
zepdrix (zepdrix):
Solve for x! :)
OpenStudy (superhelp101):
So when I solve for x that will be the answer
zepdrix (zepdrix):
Mmmmmm ya :o
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zepdrix (zepdrix):
Oh wait I made a boo boo lol, the x's cancel out lolol :D
We have to solve this a different way. hmm let's see.
OpenStudy (superhelp101):
ok
zepdrix (zepdrix):
Grr I dunno :( I can't remember how to do these darn optimization problems without calculus!
Maybe someone smart can help D:
@Zarkon @radar @dan815 @jim_thompson5910
OpenStudy (superhelp101):
Thank you though....:)
OpenStudy (superhelp101):
@Zarkon @radar @dan815 @jim_thompson5910 I reallylllllllllyyyy nneed you :(((
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