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Mathematics 8 Online
OpenStudy (superhelp101):

if the length of a rectangle is x+6 and width is x-2. Find the value of x that would allow the rectangle to have a maximum area.

OpenStudy (superhelp101):

@robtobey PLZZZZ help

OpenStudy (superhelp101):

@texaschic101 plzzzzz help!!

OpenStudy (superhelp101):

@zepdrix

OpenStudy (superhelp101):

Can you plzz help me? :((

zepdrix (zepdrix):

The rectangle which has the largest area is one in which the length is the same as the width. In other words, a square! :)

OpenStudy (superhelp101):

ok..

zepdrix (zepdrix):

|dw:1382574543091:dw|So these side lengths are equal\[\Large x+6\quad=\quad x-2\]

zepdrix (zepdrix):

Solve for x! :)

OpenStudy (superhelp101):

So when I solve for x that will be the answer

zepdrix (zepdrix):

Mmmmmm ya :o

zepdrix (zepdrix):

Oh wait I made a boo boo lol, the x's cancel out lolol :D We have to solve this a different way. hmm let's see.

OpenStudy (superhelp101):

ok

zepdrix (zepdrix):

Grr I dunno :( I can't remember how to do these darn optimization problems without calculus! Maybe someone smart can help D: @Zarkon @radar @dan815 @jim_thompson5910

OpenStudy (superhelp101):

Thank you though....:)

OpenStudy (superhelp101):

@Zarkon @radar @dan815 @jim_thompson5910 I reallylllllllllyyyy nneed you :(((

OpenStudy (superhelp101):

Can you friends help !! :((( Plzzz

OpenStudy (superhelp101):

@agent0smith Can you help me!! Plzzzz

OpenStudy (superhelp101):

@ranga anyone ?? PLZZZ :(((

OpenStudy (dan815):

|dw:1382575039318:dw|

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