Question

find all values of x such that y=0

y=x+7/5x-10 - 6/x-2 - 2/5

Answer 1

can you let y = 0
AND take -2/5 to the LHS

Answer 2

LHS?

Answer 3

Left Hand Side

Answer 4

so 2/5+0=x+7/5x-...
?

Answer 5

I know that the answer is -19 but I cannot understand how to get there

Answer 6

You have a long job to do to get theere...let me try to type for you

Answer 7

\[y=\frac{ x+7 }{ 5x-10} -\frac{ 6 }{ x-2 }-\frac{ 2 }{ 5 }\]
\[\frac{ 2 }{ 5 }=\frac{ x+7 }{ 5x-10 }-\frac{ 6 }{ x-2 }\]
\[\frac{ 2 }{ 5 }=\frac{ (x-2)(x+7)-6(5x-10) }{ (5x-10)(x-2) }\]
\[\frac{ 2 }{ 5 }=\frac{ x^2+7x-2x-14-30x+60 }{ 5x^2-10x-10x+20 }\]
\[\frac{ 2 }{ 5 }(5x^2-20x+20)=x^2-25x+46\]
\[2x^2-8x+8=x^2-25x+46\]
\[x^2+17x-36=0\]
Now you can use the Quadratic equation to find factors

Answer 8

\[x=-b \pm \frac{ \sqrt{b^2-4ac} }{ 2a}\]

Answer 9

ohhhhh

Answer 10

\[x= 1.9 and x = -18.9\approx-19\]

Answer 11

hmm so do I only take one answer?

Answer 12

the question said find all values. so both

Answer 13

the thing is I have this thing called my mathlab and I did the question and it only provided oen answer :-19