Question

There are seven consecutive numbers, and you want to divide then into subsets. Each set needs to have at least one number. How possible subsets are there?

Answer 1

Help please

Answer 2

off the top of my head, if there are \(n\) elements there are \(2^n\) subsets
but that includes the null set, which has no elements

Answer 3

so 2^n-1?

Answer 4

so i would guess at \(2^n-1\)

Answer 5

ok so 128-1=127

Answer 6

that is what i get
the question is posed a little funny, but yes

Answer 7

ok then thanks

Answer 8

that doesn't assume you use them all however

Answer 9

so perhaps that answer is not correct

Answer 10

now that i think about it, if you are looking for all the possible subsets of \(7\) elements, you need "bells number"

Answer 11

it is not really clear what "divide them in to subsets" means
but the number of ways you can partition \(n\) elements is called "bell's number"
your best bet is to google it