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Mathematics 18 Online
OpenStudy (anonymous):

limit as x approaches 0 of (sin3xsin5x)/x^2

OpenStudy (anonymous):

is that sin(3x) and sin(5x)? or sin^3(x) and sin^5(x)?

OpenStudy (anonymous):

that expression can be written as: (sin 3x)/x multiplied by (sin 5x)/x The limit of the first expression as x---> 0 is 3 The limit of the second expression as x---->0 is 5 Therefore, the product is 3(5) = 15

OpenStudy (anonymous):

It can be shown that as x---->0, (sin 3x)/x = 3 It can be shown that as x-----> 0, (sin 5x)/x = 5

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

welcome.

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