Question

xcosy=x^2+y^3 find y'

Answer 1

You have some chain rule in your near future. Let's see your best efforts.

Answer 2

\[x(-siny)y' + cosyy = 2x + 3y^2y'\]

Answer 3

That's awesome! Good work. Now some algebra and you'll be done.

Answer 4

then i simplified it, i got \[y'=(2x-cosy)/(-3y^2-xsiny)\]

Answer 5

You could pretty that up a bit.

Answer 6

It's a multiple choice worksheet, that's the answer form the have it in, but the only difference is that the -3y^2 is positive
is that a typo on the worksheet?

Answer 7

Nah, that's silly. I would go with \(y' = \dfrac{\cos(y) - 2x}{3y^{2}+x\sin(y)}\), if I had to go with something.

Answer 8

yeah but that isn't there either O.o

Answer 9

Can't help that. You got it!

Score:
You: 1
Sheet: 0

Answer 10

Thanks!! Appreciate the help