Question

can someone please help me?

Answer 1

would it be 13?

Answer 2

Yes.

Answer 3

plug in -4 into the x value(s) of the equation
the absolute value of -?? Is +??

(2*4)+5=8+5=13

Answer 4

yup. global max at x=5. If you're interested in what the graph looks like check this out

Answer 5

Yes, That would be a shift of the |x| graph 1 unit to the left.

The range remains all reals >= 0

Answer 6

I'm so confused about this one!

Answer 7

You have to understand the nature of graph shifting for this one. I'm not quite sure how to explain it without spoonfeeding.

|x|-5 would push the |x| graph 5 units down
|x+1| would push the |x| graph 1 unit left
-|x-4| would push it 4 units left

Answer 8

errr -|x-4| would push it 4 units right*

Answer 9

is that exactly how it's worded? I can't see -6 fitting any condition here

Answer 10

the last one is supposed to be x^2 if x > -6

Answer 11

I meant the conditions. Are they all < and >? No >=?

Answer 12

yes, what do you mean? like if any of them have a line under?

Answer 13

Yeah. You understand why -6 is not < -6, right? -6 is also not < -7

Answer 14

yup, i understand that. but would my answer be correct?

Answer 15

No. The question is logically wrong. There literally is no answer. I'm not sure what to say. -6 doesn't fit any of the given conditions :V

Answer 16

ermmmm

Answer 17

may i interject?

Answer 18

please do. If you embarrass me do it politely while I go hide in a corner

Answer 19

apparently less than or equal to is treated as less than

Answer 20

similarly, greater than or equal to is treated as greater than

Answer 21

oooooooh. I guess it's safe to assume 21 if -7 < x < -6 meant less than?

Answer 22

yes

Answer 23

so what it would it become?

Answer 24

21. Technology man...

Answer 25

so it would fall under the piecewise-defined function of -7<x<-6

Answer 26

I would need further clarification on this one with the other math peeps in here or a professor. I am reading and learning proofs (for improvement in math knowledge) and I am finding out some stuff that never occurred in any of my lessons before.

Answer 27

that's an inverse function now…

Answer 28

Is skeletor jesus invading my territory?

Answer 29

no. you can continue and you're doing a wonderful job btw

Answer 30

You can continue with this problem if you'd like. I just don't think the whole advanced math proofs will come into relevancy to OP.

Answer 31

would my answer be correct or not?

Answer 32

you shouldn't rely on us telling you if you're right or wrong.
we can give you some clarifications on concepts, but the rest of the work has to be done by you @adrianajones

my system of helping does not involve solving or showing you the solution to your problem, but providing a problem of the same conceptual weight and show you how to break them down into something more comprehensible. of course, I might break this self-imposed rule once in a while but it would depend on the situation.

Answer 33

well i asked if my answer was right or wrong? that's all i wanted to know. otherwise i know i will have to work on that concept.

Answer 34

is there any reason you doubt your answer?

Answer 35

show me your solution

Answer 36

@skullpatrol is about to shed some light, his method of helping might be more lenient or favorable to you.

Answer 37

@nincompoop please continue :)