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Mathematics 21 Online
OpenStudy (osanseviero):

Inverse logarithmic function

OpenStudy (osanseviero):

So they want the inverse of \[F(x)=\ln \sqrt{x}\] So the inverse is \[x=\ln \sqrt{y}\]

hartnn (hartnn):

yep, now isolate y

hartnn (hartnn):

\(\Large a=\ln c \implies c = e^a \)

OpenStudy (osanseviero):

\[y=\left( e ^{x} \right)^{2}\] the 2 can go down, right?

OpenStudy (osanseviero):

y=2e^x

hartnn (hartnn):

not actually

hartnn (hartnn):

\(\Large (e^x)^2 = e^{2x}\)

OpenStudy (osanseviero):

oops, another silly mistake

OpenStudy (osanseviero):

Can someone help me demostrate that (FoFinverse)(x)=(FinverseoF)(x)=x ?

hartnn (hartnn):

demonstrate ? you have a function for verifying that ?

OpenStudy (osanseviero):

The one we just did

OpenStudy (osanseviero):

\[\ln \sqrt{e ^{2x}} = e ^{2\ln \sqrt{x}}=x\]

hartnn (hartnn):

so, f inverse = e^2x just plug in x =ln \sqrt x oh, you did it :)

OpenStudy (osanseviero):

But how and why? (I think that was a good statement)

OpenStudy (osanseviero):

And how would that be x?

hartnn (hartnn):

ln x^m = m ln x

hartnn (hartnn):

ln e =1

hartnn (hartnn):

\(\sqrt {(e^x)^2} = |e^x| \\ \ln |e^x| = x \ln e = x\)

hartnn (hartnn):

ok ?

OpenStudy (osanseviero):

so the left one is kinda obvious, so it is x

OpenStudy (osanseviero):

Oh...and the other one is with \[a ^{logaN}=\]

OpenStudy (osanseviero):

N

hartnn (hartnn):

\(\huge a^{\log_aN}=N\)

hartnn (hartnn):

yes

OpenStudy (osanseviero):

:) Now I understand, thanks for fifth time, just one more question :P

hartnn (hartnn):

welcome ^_^

OpenStudy (osanseviero):

Which would be the domain and the range of the first, normal function?

hartnn (hartnn):

domain of ln sqrt x ?

hartnn (hartnn):

since its sqrt x, x>= 0 since its ln, sqrt x >0 in all, x>0

OpenStudy (osanseviero):

so the range of the inverse is x>0

OpenStudy (osanseviero):

Wish me good luck tomorrow

hartnn (hartnn):

yes! best of luck! hope you get full marks :)

OpenStudy (osanseviero):

I hope so, this will be a hard examn...all types of functions, trigonometric identities, operations with functions

hartnn (hartnn):

if you have practices enough, nothing is hard :)

OpenStudy (osanseviero):

Thanks for the help all night!

hartnn (hartnn):

you're welcome ^_^

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