if a plane mirror is shifted by an angle thita what will be the angle of reflection?
Angle of incidence = angle of reflection |dw:1382603754032:dw|
So the angle between the incident and reflected ray is \[ \alpha + \alpha = 2 \alpha \] Now we rotate the plane mirror by angle theta (the rotation shown as the change in angle between the original normal, n, and the new normal, n' |dw:1382603893594:dw| When the mirror is shifted by an angle theta while holding the incident ray steady, the angle of incidence is still equal to the angle of reflection, therefor, \[(\theta + \alpha) + (\theta + \alpha) = 2\theta + 2\alpha\] The reflected ray gets rotated a total of 2 theta. Measured from the original normal, if plane mirror is rotated an angle theta, the angle of reflection is \[ 2\theta + \alpha\]
Join our real-time social learning platform and learn together with your friends!