Question

Find the least ordered polynomial passing through the following points (0,0), (1,0), (2,4), (5,1)

Answer 1

you know it'll be a 4th order polynomial of the form
f(x) = x * (cubic)

Answer 2

yeah the polynomial will be 4-1=3rd order, a cubic

Answer 3

the at least ordered is the least power of x , in polynomial
f(x)=d is the least
then
f(x)=bx+d
then
f(x)=ax^2+bx+d
and so on

Answer 4

it'll be 4th order, as 4 points are given...

Answer 5

n-1

Answer 6

oh yeah, oops
then its even simpler

Answer 7

its 4'th order if its aproximation

Answer 8

f(x) = x (quadratic)
y= x* (ax^2+bx+c)
take different points except 0,0,
3 equations, 3 unknowns

Answer 9

y= x* (ax^2+bx+c)
1,0
0 = a+b+c

Answer 10

assuming points are
0,0 1,0 2,4 5,1

Answer 11

oh yeah @hartnn\[\cancel{(0,1)} (1,0) \] sorry