Question

Solve the triangle.

A = 51°, b = 14, c = 6

Answer 1

u can use the sine rule here:
a/sin A = b/sin B = c/sin C
\[\frac{ a }{ \sin A }= \frac{ b }{ \sin B }= \frac{ c }{ \sin C }\]

Answer 2

or u can use the cosine rule:
\[c^2 = a^2 + b^2 - 2ab \times \cos(C)\]
rearrange as you currently know A, and solve for c... etc

Answer 3

so which will u use @Loveiskey18 ?

Answer 4

The second formula.

Answer 5

right, first off, and what did u get for A?

Answer 6

dammit, sorry, little "a"?

Answer 7

2601.

Answer 8

nevermind, disregard that

Answer 9

You know what, let's use the first formula, I thought that the second one was going to be simple, that is why I chose it...

Answer 10

will be difficult until u know both one side and it's corresponding angle, otherwise you'll have to do some funky subsitiution... save the sine rule for after you solve "a" using cosine rule

Answer 11

so a^2 = b^2 + c^2 -2*b*c* cos (A)

Answer 12

a^2 = b^2 + c^2 -2*b*c* cos (A)
a^2 = 14^2 + 6^2 -2*14*6* cos (51)
... so times it all out and solve, u get
a^2 = 126.27
so a = 11.2372 ...ish

now use the sine rule from here, yeah?

Answer 13

yes

Answer 14

sweet, good luck!
did the above all make sense tho?

Answer 15

Actually it did. Thank You, I really do appreciate your help. :)