Question

hay ns try this maybe?

Answer 1

hai

Answer 2

y = -0.0001x^8 + 0.0028x^7 – 0.0579x^6 + 0.6421x^5 – 4.109x^4 + 15.4107x^3 – 33.384x^2 + 39.4438x – 11.1523
\[y = -0.0001x^8 + 0.0028x^7 – 0.0579x^6 + 0.6421x^5 – 4.109x^4 + 15.4107x^3 – 33.384x^2 + 39.4438x – 11.1523 \]
so
y' = -0.0008x^7 + 0.0196x^6 - 0.3474x^5 + 3.2105x^4 - 16.436x^3 + 46.2321x^2 - 66.768x + 39.4438
\[y' = -0.0008x^7 + 0.0196x^6 - 0.3474x^5 + 3.2105x^4 - 16.436x^3 + 46.2321x^2 - 66.768x + 39.4438\]

Answer 3

hey
so with me so far?

Answer 4

wait, what are x and y in this eqn?

Answer 5

kind of u found the derivative, hey?

Answer 6

yep

Answer 7

idk what x and y are smthn to do with sales,, i think its irrelevant tho

Answer 8

not really, if x is sales it changes everything
if y is sales we're on track tho...
is x days or product sold or... idk, it's kinda important

Answer 9

x is months and y is sales

Answer 10

cools, and u need to find the months with the most sales? and the one with the least?
so those will be the turning points on a graph of x vs y
so if we find derivative ( y' )
then equate that to 0, we will have x values when y' = 0, which are the turning points of original equation

with me so far?

Answer 11

ahh yeah that makes sense remmber hearing that in the lesson lool ;P

Answer 12

umm... i think ur equation only has one "real" solution, the rest all involve imaginary numbers

Answer 13

really? *sigh*

Answer 14

well... ur equation plots out to something like this:


...ish
so there;s really only a peak... no truoghs...