Question

^3sqrt 3x-1=2

Answer 1

\[\sqrt[3]{(3x-1)}=2\]
?

Answer 2

yeah

Answer 3

Use, that:
\[(\sqrt[q]{a})^m=a^{\dfrac{m}{q}}\]

Answer 4

Uhm yeah I'm really bad at math so...

Answer 5

Give it a try :)

Answer 6

I know how to solve regular square root equations but with the exponent on the outside I don't know what to do.

Answer 7

Practice makes perfect, it's basic algebra:
You'll get:
\[(3x-1)^{\dfrac{1}{3}}=2\]

Answer 8

Okay, I can solve it from there.

Answer 9

Sounds good :)!
Just write back, if you need anymore help :)

Answer 10

Okay, I'm confused again lol I don't understand how to solve it with the 1/3

Answer 11

Sorry it took so long, i had to go on another pc :)
\[(3x-1)^\dfrac{1}{3}=8^{\dfrac{1}{3}}\]
<=>
\[(3x-1)=8\]

Answer 12

The trick is to write 2 as a number x to the power of \[\dfrac{1}{3}\]

Answer 13

Just for the sake of it:
\[2=\sqrt[3]{8}=8^{\dfrac{1}{3}}\]