Question

if kinetic energy is increases by 300% then change in momentum is
100%
200%
300%

Answer 1

\[ K_i = \frac{1}{2}mv_i^2 = \frac{p_i^2}{2m} \]
\[K_f = \frac{p_f^2}{2m}
\\ p_f = np_i
\\K_f = 3K_i \]
\[3K_i =3\frac{p_i^2}{2m} = \frac{(np_i)^2}{2m}
\\ 3p_i^2 = n^2 p_i^2
\\n = \sqrt 3 \]

The change in the square of the momentum is 300%, but the change in the momentum itself is
\[ (100\sqrt3) \% \] :)

Answer 2

Remember that "increased by 300%" means "multiplied by 4".

Answer 3

well fiddle. You're right.

Answer 4

substituting 4 for 3, the last expression is then
\[ 4p_i^2 = n^2p_i^2 \]
\[ n = 2\]

Answer 5

so if you double the momentum, you quadruple the kinetic energy!

Answer 6

HOW Kf = 3 Ki ?? @AllTehMaffs MASTER :)

Answer 7

I misread the original question - it should be Kf = 4 Ki ^_^

Answer 8

But from where we get 4 ???

Answer 9

from the 300% increase.

If you have energy K, then 300% increase = 4K

so you have an initial K, Ki, and final K, Kf
Ki = K
Kf = 4K

Kf = 4Ki

Answer 10

How 300 % = 4 ??? SIR :/

Answer 11

start with K
100% increase = 2K
200% increase = 3K
300% increase = 4K

(I got it wrong, too :P)

Answer 12

Its ok ..:) So NOw what is answer ??

Answer 13

n = 2 ;
pf = 2pi

increased by 100% percent

The post two above your first comment ^^