Question

if (3x^2)+7=0 then (x-1/3)^2 how do you suppose to solve this problem?

Answer 1

Well for the first equation we have 3x^2 + 7 = 0 so the the (3x^2) part needs to equal -7 to make the equation work. So we would do 3x^2 = 7 . Can you find x from that? And then you would just plug X into the next equation to find the answer.

Answer 2

I made a mistake. 3x^2 = -7 not 7 my bad

Answer 3

so the first expression is needed to solve for the second one?

Answer 4

let me solve

Answer 5

Yes, because you need to make it equal to 0? What class is this for? I am not sure how far you need to go with this. Cuase you would maybe have to use imaginary numbers using i

Answer 6

it is a problem from a practice test i know the answer by looking it up on the answer key but I would like to know the steps

Answer 7

And is the question states if 3x^2+7 = 0 then what is the value of ((x-1)/3)^2

Answer 8

is that the question ^ because what u said is a little different

Answer 9

if 3x^2-2x+7=0, then (x-1/3)^2

Answer 10

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Answer 11

3x^2 + 7 = 0
3x^2 = -7
3x = square root of -7 which then you would have to use imaginary numbers
3x = isquareroot of 7
x = i square root of 7/3

Answer 12

And i do not understand so the queston is if 3x^2-2x+7=0, then (x-1/3)^2?? but why are they giving you the second equation, do they want the value of (x-1/3)^2

Answer 13

the answer is -20/9

Answer 14

im not sure

Answer 15

I dont know sorry, the question just doesnt make sense, i dont know what they are looking for.

Answer 16

ok, thanks for your help anyhow

Answer 17

\[3x ^{2}-2x+7=0,3\left( x ^{2}-\frac{ 2 }{ 3 }x+\frac{ 1 }{ 9 }-\frac{ 1 }{9} \right)+7=0\]
\[3\left( x-\frac{ 1 }{ 3 } \right)^{2}-3*\frac{ 1 }{9 }+7=0\]
\[3\left( x-\frac{ 1 }{ 3 } \right)^{2}=\frac{ 1 }{3}-7=-\frac{ 20 }{3 }\]
\[\left( x-\frac{ 1 }{ 3 } \right)^{2}=-\frac{ 20 }{9 }\]

Answer 18

Thank You!

Answer 19

if i can ask, -1/9 & 1/9 come from 1/3^2

Answer 20

how come one is negative and one positive

Answer 21

\[\to complete thesquare ,if coefficient of x ^{2} is 1,then add \left( \frac{coefficient of x}{ 2 } \right)^{2}\]

Answer 22

ok!