Question

Algebra help please!

Answer 1

\[a=\dfrac{x_{2}-x_{1}}{y_{2}-y_{1}}\]

Answer 2

woops typeo

Answer 3

Home it's the the other way round, y over x xD

Answer 4

This is the right one you gotta use:\[a=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\]

Answer 5

Ye i saw that hehe :P

Answer 6

To find the gradient you use Homes equation with the y's on top and the x's below. So for the first one, you have (-7-3)/(5-1) = -10/4 = -5/2

The second one you do (5-2)/(2-1) = 3/1 = 3 :D

Answer 7

^

Answer 8

can u give answer?

Answer 9

You gotta learn, there's no good in just giving you the answers

Answer 10

The point of the test is to test if you can do it, why take it if you are gonna cheat xD?

Answer 11

You've got the coordinates:
1. \[(x_1,y_1)=(1,3)\]\[(x_2,y_2)=(5,-7)\]
use the formula:
\[a=\dfrac{y_2-y_1}{x_2-x_1}\]

Answer 12

would it b 6?

Answer 13

@TripleC allrdy calculated the first one

Answer 14

And the second one xD, home you are so helpful it is unreal

Answer 15

i emant 7 lol

Answer 16

meant

Answer 17

for question 6 is 3 right? whats question 5 & 7 than?

Answer 18

Hehe thanks @TripleC , i do math in my sparetime :), why not help people a little :)
Question 6:
you've got the coordinates:
\[(x_1,y_1)=(1,2)\]and\[(x_2,y_2)=(2,5)\]
Insert these into this formula:
\[a=\dfrac{y_2-y_1}{x_2-x_1}\]

Answer 19

@HomeZone That's pretty much my attitude as I have 15 hours of maths tutoring to me so I kinda put it to use, but bejabus.

Just incase, \[y _{2}\]
simply means the second y co-ordinate
and \[y _{2}\]
means the first y co-ordinate. The exact same applies for the x's.

Answer 20

You're calculating the slope of a linear function such as: \[f(x)=ax+b\]
Question 6:
\[a=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{5-2}{2-1}=\dfrac{3}{1}=3\]
So yes you were right :)

Answer 21

I didn't see your post @tesla117 before :)

Answer 22

would 5 be 2/5
6 be 3
7 be 2/7

Answer 23

you got question 6 right the 2 others are wrong :)

Answer 24

what are the other two? @HomeZone

Answer 25

would 5 b -2/5?

7 be 7?

Answer 26

If you know basic algebra this shouldn't be a problem:
Question 5:\[a=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-7-3}{5-1}=?\]
Question 7: \[a=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{-3-4}{2}=?\]

Answer 27

I guess you figured it out :)