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Chemistry 18 Online
OpenStudy (amtran_bus):

Write a balanced chemical equation Lead IV oxide decomposes to yield lead II oxide and a colorless gas?

OpenStudy (amtran_bus):

Why is it not PbO2---> Pb+O2?

OpenStudy (amtran_bus):

@abb0t can you help me?

OpenStudy (joannablackwelder):

Lead(II) oxide is PbO.

OpenStudy (amtran_bus):

So PbO2----> PbO+O2?

OpenStudy (amtran_bus):

Of course that is not balanced.

OpenStudy (abb0t):

they said Lead (IV) oxide, not Lead (II), joanna.

OpenStudy (joannablackwelder):

You got it. :)

OpenStudy (joannablackwelder):

How would you balance it?

OpenStudy (joannablackwelder):

I don't understand your comment, @abb0t.

OpenStudy (amtran_bus):

Sorry, site is slow for me

OpenStudy (amtran_bus):

@JoannaBlackwelder you mean balance PbO2--->PbO+O2? Can u help me?

OpenStudy (joannablackwelder):

Sure. Since the lead is balanced, oxygen is where to start. The only way to have an even number of O on the product side is to have 2PbO.

OpenStudy (joannablackwelder):

To get lead balanced again, we will need 2PbO2.

OpenStudy (joannablackwelder):

Count atoms to confirm. 2 leads on each side and 4 oxygens. Done!

OpenStudy (amtran_bus):

So 2PbO2--->2PbO+O2?

OpenStudy (amtran_bus):

Thanks!

OpenStudy (joannablackwelder):

Yes. No worries. :)

OpenStudy (amtran_bus):

Can you check this last one?AgNO3 (aq) with BaO I have heard the BaO makes this impossible, but I still have to have an answer. I know it is not 2Ag+ (aq) +o2- (aq) yields Ag2O (s) because I tried it.

OpenStudy (amtran_bus):

Net ionic equation

OpenStudy (amtran_bus):

Here is what it says to do

OpenStudy (amtran_bus):

Thanks Joanna.

OpenStudy (amtran_bus):

Is the result AgO+BaNO3? and AgO the solid? I have heard something else happens, but the website wants it this way.

OpenStudy (joannablackwelder):

There is a solubility table at the bottom of this website.

OpenStudy (amtran_bus):

After checking it, I feel like my prediction is correct.

OpenStudy (joannablackwelder):

The insoluble product is silver oxide, but for charges to balance the compound must be Ag2O.

OpenStudy (amtran_bus):

ohhh

OpenStudy (amtran_bus):

So would it be Ag+ +O2- -----> Ag2O?

OpenStudy (amtran_bus):

for the final answer?

OpenStudy (joannablackwelder):

Right, except that it is not balanced.

OpenStudy (amtran_bus):

Thanks, I can balance it later. I need to go.

OpenStudy (amtran_bus):

Well, can you help me balance it?

OpenStudy (joannablackwelder):

Ok. You're welcome.

OpenStudy (amtran_bus):

Sorry

OpenStudy (joannablackwelder):

The oxygens are already balanced, so look at the Ag first.

OpenStudy (amtran_bus):

I mean 4Ag+O2-->2Ag2O

OpenStudy (joannablackwelder):

Close. There is only one O in the reactants (the 2 is from the charge)

OpenStudy (joannablackwelder):

So, you only need one more Ag in the reactants. 2Ag+(aq) + O2-(aq) -> Ag2O(s)

OpenStudy (amtran_bus):

Thank you so much. You helped me get about 6 extra points today.

OpenStudy (joannablackwelder):

No worries. Glad I could help. :)

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