Write a balanced chemical equation
Lead IV oxide decomposes to yield lead II oxide and a colorless gas?
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OpenStudy (amtran_bus):
Why is it not PbO2---> Pb+O2?
OpenStudy (amtran_bus):
@abb0t can you help me?
OpenStudy (joannablackwelder):
Lead(II) oxide is PbO.
OpenStudy (amtran_bus):
So PbO2----> PbO+O2?
OpenStudy (amtran_bus):
Of course that is not balanced.
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OpenStudy (abb0t):
they said Lead (IV) oxide, not Lead (II), joanna.
OpenStudy (joannablackwelder):
You got it. :)
OpenStudy (joannablackwelder):
How would you balance it?
OpenStudy (joannablackwelder):
I don't understand your comment, @abb0t.
OpenStudy (amtran_bus):
Sorry, site is slow for me
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OpenStudy (amtran_bus):
@JoannaBlackwelder you mean balance PbO2--->PbO+O2?
Can u help me?
OpenStudy (joannablackwelder):
Sure. Since the lead is balanced, oxygen is where to start. The only way to have an even number of O on the product side is to have 2PbO.
OpenStudy (joannablackwelder):
To get lead balanced again, we will need 2PbO2.
OpenStudy (joannablackwelder):
Count atoms to confirm. 2 leads on each side and 4 oxygens. Done!
OpenStudy (amtran_bus):
So 2PbO2--->2PbO+O2?
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OpenStudy (amtran_bus):
Thanks!
OpenStudy (joannablackwelder):
Yes. No worries. :)
OpenStudy (amtran_bus):
Can you check this last one?AgNO3 (aq) with BaO
I have heard the BaO makes this impossible, but I still have to have an answer.
I know it is not 2Ag+ (aq) +o2- (aq) yields Ag2O (s) because I tried it.
OpenStudy (amtran_bus):
Net ionic equation
OpenStudy (amtran_bus):
Here is what it says to do
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OpenStudy (amtran_bus):
Thanks Joanna.
OpenStudy (amtran_bus):
Is the result AgO+BaNO3? and AgO the solid?
I have heard something else happens, but the website wants it this way.