Rewrite the rational exponent as a radical by extending the properties of integer exponents.

2 to the 7 over 8 power, all over 2 to the 1 over 4 power

the eighth root of 2 to the fifth power

the fifth root of 2 to the eighth power

the square root of 2 to the 5 over 8 power

the fourth root of 2 to the sixth power

Question

Rewrite the rational exponent as a radical by extending the properties of integer exponents.

2 to the 7 over 8 power, all over 2 to the 1 over 4 power

 the eighth root of 2 to the fifth power

 the fifth root of 2 to the eighth power

 the square root of 2 to the 5 over 8 power

 the fourth root of 2 to the sixth power

undeadknight26 · Answer

@SolomonZelman @Hero please help!

undeadknight26 · Answer

@ash2326 @bigeyes420 @Compassionate please help!

anonymous · Answer

how did u do that tagg me in it

campbell_st · Answer

the index law for division of the same base is subtract the powers

$$\frac{x^a}{x^b} = x^{a - b}$$

apply this to your question

undeadknight26 · Answer

the at sign and then a name

undeadknight26 · Answer

But first i would need common denominators right>

undeadknight26 · Answer

so its the second one?

campbell_st · Answer

nope , you have 

$$2^{\frac{7}{8} - \frac{1}{4}} = $$

undeadknight26 · Answer

5 over 8?

campbell_st · Answer

then you need to know about indexes for radicals 

$$\sqrt[a]{x^b}=x^{\frac{b}{a}}$$

now apply this to you part solution 

$$2^{\frac{5}{8}}$$

undeadknight26 · Answer

8/2^5?

campbell_st · Answer

I think that makes sense... which answer choice would it be..?

undeadknight26 · Answer

The first one?

campbell_st · Answer

yep thats it

undeadknight26 · Answer

Can you help me with 4 more please?

undeadknight26 · Answer

or is that 2 much?

campbell_st · Answer

sorry I'm about to head off and do some jobs...

undeadknight26 · Answer

Ok thanks!  Go help the world!

anonymous · Answer

Did that end up being the right answer? @undeadknight26

anonymous · Answer

was this correct