Question

Help me please with this Algebra Problem!!! :)

Answer 1

well lets put 7x^3 – 28x^2 + 3x – 12
here some of the terms don't have the same common factor, like 7 and 28 can be factored by 7 but 3 and -12 cant. So what you do is, factor the first two terms individually. 7x^3 – 28x^2
7x^3 = 7 time x time x times x
28x^2 = 7 times 2 times 2 times x times x
in these two, the only same numbers are 7 times x times x, which is 7x^2.
so now find what multiplied y 7x^2 can make the original two numbers. like this
7x^2(x -4)
now do the same with the last two terms. 3x -12
3 = 3 times x
-12 = 4 times 3
The only similarity is 3
so now find what multiplied by 3 makes the original last two numbers: 3x -12
3(x - 4) so now you have
7x^2(x -4) 3(x-4)
now you do this:
(x – 4)(7x2 + 3) < ---- Answer
and that's all.

Answer 2

sorry for taking so long, its just a lot of stuff to write and I tried to explain as much as possible, ask me if you have any problem

Answer 3

Thank you, you're amazing :D

Answer 4

lol thx xD