Question

Calculus!!!!! Does anybody know how to do it! I NEED help and I have been waiting for a long time for help.

Answer 1

right! okay I need help with finding absolute extrema.

Answer 2

2(3-x) [-1,2]

Answer 3

t^2/t^2+3

Answer 4

original one, please. I don't understand what you are writing

Answer 5

on the closed interval [-1,1]

Answer 6

first off, cal1 or cal3?
second, what is the original function?

Answer 7

Okay so it says find the absolute extrema of the function on a closed interval.
f(x)=2(3-x), [-1,2]
I don't know I am in AP calculus

Answer 8

so, f(x) = 6 - 2x?

Answer 9

so first I find the derivative? right?

Answer 10

yup

Answer 11

okay and then I take the derivative and plug it into my calculator?

Answer 12

nup, take steps, please
f'(x) =?

Answer 13

-2

Answer 14

AP calculus student, do you have to use calculator to solve it?

Answer 15

No it just said that in my book. I can solve it without a calculator

Answer 16

yes, so, in the interval[-1,2] the extrema don't depend on f'(x) , you have 2 candidate points, -1, 2 only. Plug them into f(x) you have f(-1) = 8 and f(2) = 2
so, local max at -1 and local min at 2. done

Answer 17

okay so you don't even have to use the derivative? You just can plug in a solve. Well that is way easier.

Answer 18

f'(x) = negative number (-2) show that the function decreases. that's it

Answer 19

okay thank you! :)

Answer 20

ok