why am i not getting this question right? I took the
sqrt of (.83)(1.74*10^-5) then the -log of the answer I got.
Find the pH of 0.83 M CH3COOH. Ka = 1.74 x 10-5M.

also can someone explain this to me please? Calculate the approximate [OH-] and [NH4+] in a 0.66 M ammonia solution, NH3(aq).

NH3(aq) + H2O(l) ↔ OH-(aq) + NH4+(aq). Kb = 1.75 x 10-5M.

Question

why am i not getting this question right? I took the 
sqrt of (.83)(1.74*10^-5) then the -log of the answer I got.
Find the pH of 0.83 M CH3COOH. Ka = 1.74 x 10-5M. 


also can someone explain this to me please? Calculate the approximate [OH-] and [NH4+] in a 0.66 M ammonia solution, NH3(aq).

NH3(aq) + H2O(l) ↔ OH-(aq) + NH4+(aq). Kb = 1.75 x 10-5M.

vincent-lyon.fr · Answer

You should find pH = 2.4

anonymous · Answer

so i did do it right..my calculator keeps saying something different, but got it this time. Thanks